At 11:39 +0200 on 20/1/99, gjerde@icebox.org wrote:
>
> This is the query that breaks:
> SELECT memberaccess.access
> FROM memberaccess
> WHERE memberaccess.MemberID = members.ID
> AND members.username LIKE 'gjerde';
>
> This last query will give the error message on top.
> The sql statements to create my tables are below.
You are comparing a value of type INT8 with one of type INT4 . I suppose
this *should* work OK, with one type being converted to the other, but as I
have seen so many messages to the mailing lists about broken INT8 support,
I think you better avoid it.
Think: if you are restricting by MemberID = ID, it makes sense that the two
fields should have the same domain. That is, since members.ID, a primary
key, will never have the big values associated with an INT8, it makes no
sense to define MemberID as INT8.
Herouth
--
Herouth Maoz, Internet developer.
Open University of Israel - Telem project
http://telem.openu.ac.il/~herutma
